দুটি ছক্কা একই সাথে নিক্ষেপ করা হয় এবং তাদের উপর উপস্থিত সংখ্যার যোগফল উল্লেখ করা হয়। যোগফল 12 হওয়ার সম্ভাবনা কত?

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NTPC CBT-I (Held On: 30 Dec 2020 Shift 1)
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  1. \(\frac{1}{36}\)
  2. 3
  3. 36
  4. \(\frac{12}{36}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{1}{36}\)
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Detailed Solution

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প্রদত্ত:

দুটি ছক্কা একসাথে নিক্ষেপ করলে সম্ভাব্য ফলাফলের সংখ্যা: 6 × 6 = 36

(1,1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

অনুসৃত সূত্র:

সম্ভাব্যতা = অনুকূল ফলাফলের সংখ্যা ÷ মোট ফলাফলের সংখ্যা

গণনা:

যোগফল সহ ফলাফলের সংখ্যা 12 (6, 6) = 1

∴ নির্ণেয় সম্ভাব্যতা = 1/36

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