Question
Download Solution PDFCompaction Test 1 - Weight of hammer = 10 kg, Height of fall = 500 mm, Number of layers = 3, Number of blows per layer =25.
Compaction Test 2- Weight of hammer = 5 kg, Height of fall = 250 mm, Number of layers = 6, Number of blows per layer = 25.
The ratio of compactive energy of compaction test 1 to that of compaction test 2 is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
To find the ratio of compactive energy between two compaction tests, we use the formula for compactive energy. The compactive energy is calculated using the weight of the hammer, height of fall, number of blows per layer, and the number of layers.
Calculation:
For Compaction Test 1:
- Weight of hammer (
W1 W1 W1 ) = 10 kg - Height of fall (
h1 h1 h1 ) = 500 mm = 0.5 m - Number of layers (
L1 L1 L1 ) = 3 - Number of blows per layer (
B1 B1 B1 ) = 25
Compactive Energy for Test 1:
For Compaction Test 2:
- Weight of hammer (
W2 W2 W2 ) = 5 kg - Height of fall (
h2 h2 h2 ) = 250 mm = 0.25 m - Number of layers (
L2 L2 L2 ) = 6 - Number of blows per layer (
B2 B2 B2 ) = 25
Compactive Energy for Test 2:
Ratio of Compactive Energy (Test 1 to Test 2):
Last updated on May 28, 2025
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