Question
Download Solution PDFDimension of specific heat is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Specific heat or specific heat capacity of a body is the amount of heat required for a unit mass of the body to raise the temperature by 1 degree celsius.
It is denoted by “C” or “S”.
S = (Q /m Δ t)
where S = specific heat of a substance, Q = Heat supplied to the object, m = mass of the substance, Δ t = change in temperature
Dimensional formula of Energy [E] = [ML2t-2]
S = (Q/m Δt)
Q is heat supplied which is a type of energy
So [Q] = [E] = [ML2t-2]
[Mass] = [M]
[Temperature] = [T]
\(\left[ S \right] = \;\frac{{\left[ Q \right]}}{{\left[ M \right]\left[ {Temperature} \right]}} = \frac{{M{L^2}{t^{ - 2}}}}{{M \times T}} = {M^0}{L^2}{t^{ - 2}}{T^{ - 1}}\)
Last updated on May 19, 2025
-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been released on its official website.
-> JKSSB JE exam will be conducted on 10th August (Civil), and on 27th July 2025 (Electrical).
-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering.
-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025.
-> JKSSB JE Online Application form will be activated from18th May 2025 to 16th June 2025
-> Candidates who are preparing for JKSSB JE can download syllabus PDF from official website of JKSSB.
-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.
-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.