यदि x = t- 1 और y = t2 + t है तो \(\rm dy\over dx\) का मान क्या है?

  1. \(\rm \frac{1}{2t}\)
  2. 2t
  3. 1 + \(\rm \frac{1}{2t}\)
  4. इनमें से कोई नहीं 

Answer (Detailed Solution Below)

Option 3 : 1 + \(\rm \frac{1}{2t}\)
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Detailed Solution

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संकल्पना:

अवकलज का श्रृंखला नियम:

  • \(\rm \frac{d}{dx}f(g(x))=\frac{d}{d\ g(x)}f(g(x))\times \frac{d}{dx}g(x)\)
  • \(\rm \frac{dy}{dx}=\frac{dy}{du}\times \frac{du}{dx}\)


गणना:

यह दिया गया है कि x = t2 - 1

⇒ \(\rm dx\over dt\) = 2t

और, y = t2 + t.

⇒ \(\rm dy\over dt\) = 2t + 1

अब, \(\rm \frac{dy}{dx}=\frac{dy}{dt}\times \frac{dt}{dx}\) (अवकलज का श्रृंखला नियम)

⇒ \(\rm \frac{dy}{dx}=(2t+1)\times \frac{1}{2t}\) = 1 + \(\rm \frac{1}{2t}\)

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