Question
Download Solution PDFप्रथम कोटि अभिक्रिया में प्रतिकारक की सान्द्रता 1.0 M से 0.25 M, 20 मिनट में घटती है तो k का मान ________ है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
प्रथम कोटि अभिक्रिया की गतिज
- प्रथम कोटि अभिक्रिया के लिए, अभिक्रिया की दर अभिकारक की सांद्रता के समानुपाती होती है।
- प्रथम कोटि अभिक्रिया के लिए एकीकृत दर नियम इस प्रकार दिया गया है:
\( \ln \left(\frac{[R]_0}{[R]}\right) = kt \), जहाँ:- \([R]_0\) अभिकारक की प्रारंभिक सांद्रता है।
- [R] समय t पर अभिकारक की सांद्रता है।
- k दर स्थिरांक है।
- t समय है।
गणना:
- दिए गए डेटा:
- प्रारंभिक सांद्रता \([R]_0 = 1.0 \, M\)
- अंतिम सांद्रता \([R] = 0.25 \, M\)
- समय \(t = 20 \, minutes\)
- प्रथम कोटि अभिक्रिया दर नियम का उपयोग करके:
- \(\ln \left(\frac{[R]_0}{[R]}\right) = kt \)
- \(\ln \left(\frac{1.0}{0.25}\right) = k \times 20 \, minutes\)
- \(\ln(4) = k \times 20\)
- \(k = \frac{\ln(4)}{20} \approx \frac{1.386}{20} \approx 0.06932 \, \text{min}^{-1}\)
सही उत्तर (1) 0.06932 है।
Last updated on Jun 18, 2025
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