Question
Download Solution PDFसमानांतर तल 3x + y + 3z = 8 और 9x + 3y + 9z = 15 के बीच की दूरी क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
दो समानांतर तल ax + by + cz + d1 = 0 और ax + by + cz + d2 = 0 के बीच की दूरी \(\rm |\frac{d_1-d_2}{\sqrt{a^2+b^2+c^2}}|\) है।
गणना:
यहाँ, 3x + y + 3z = 8 और 9x + 3y + 9z = 15
9x + 3y + 9z = 15 को 3 से विभाजित करने पर हमें निम्न प्राप्त होता है
अब, 3x + y + 3z = 8 और 3x + y + 3z = 5 के बीच की दूरी
\(\rm= |\frac{8-5}{\sqrt{3^2+1^2+3^2}}|\\ =\frac{3}{\sqrt{19}}\)
अतः विकल्प (3) सही है।
Last updated on May 30, 2025
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