Question
Download Solution PDFIf 2x = 4y = 8z and \(\frac{1}{2x}+\frac{1}{4y}+\frac{1}{4z}=4\), then the value of x is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
2x = 4y = 8z
\(\frac{1}{2x}+\frac{1}{4y}+\frac{1}{4z}=4\)
Calculation:
\(\frac{1}{2x}+\frac{1}{4y}+\frac{1}{4z}=4\)---- (1)
2x = 4y = 8z
⇒ 2x = 22y = 23z
⇒ x = 2y = 3z
Converting y and z in x
2y = x, so 4y = 2x
3z = x, so 4z = 4x/3
Using the above value in equation (1)
⇒ \(\frac{1}{2x}+\frac{1}{2x}+\frac{3}{4x}=4 \)
⇒ 7/4x = 4
∴ x = 7/16
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