In a 1200 m race, bike A beats bike B by 100 m. Bike B beats bike C by 100 m in a 600 m race. If bike A beats bike C by 30 sec in a 720 m race, then what is the speed of bike C?

Question

Question

This question was previously asked in

SSC CGL 2022 Tier-I Official Paper (Held On : 03 Dec 2022 Shift 4)

Answer 1

Given:

In a 1200 m race, bike A beats bike B by 100 m. Bike B beats bike C by 100 m in a 600 m race.

Concept used:

Speed = Distance/Time

Calculation:

When bike A covers 1200 m bike B covers 1100 m

Ratio of speed = 12 : 11

Again,

When bike B covers 600 m bike c covers 500 m

Ratio of speed = 6 : 5

Ratio of speed of A, B, and C = 72 : 66 : 55

So, when bike A covers 720 m then bike C covers 550 m

So, difference = 720 - 550

⇒ 170 m

Now,

Bike C will cover the remaining 170 m in 30 sec

So, speed of bike C = 170/30

⇒ \({{17} \over 3}\) m / sec

∴ The speed of bike C \({{17} \over 3}\) m / sec.