In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be:

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  1. 0.25 mm
  2. 0.75 mm
  3. 0.50 mm
  4. 1 mm

Answer (Detailed Solution Below)

Option 1 : 0.25 mm
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Calculation:
The fringe separation in a Young's double slit experiment is given by the formula:

y = (λ × D) / d

Where:

  • λ is the wavelength of light
  • D is the distance between the slits and the screen
  • d is the distance between the slits

Substitute the given values:

  • λ = 500 nm = 500 × 10-9 m
  • D = 1 m
  • d = 2 mm = 2 × 10-3 m

The fringe separation (y) is:

y = (500 × 10-9 × 1) / (2 × 10-3) = 0.25 mm

The correct answer is: 0.25 mm

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