In the circuit for relaxation oscillator, with RBB = 5 kΩ, η = 0.6, Vv = 1 V, Iv = 10 mA and Ip = 10 μA, the value of RB1 is:

This question was previously asked in
KVS TGT WET (Work Experience Teacher) 23 Dec 2018 Official Paper
View all KVS TGT Papers >
  1. 3 kΩ
  2. 4 kΩ
  3. 1 kΩ

Answer (Detailed Solution Below)

Option 2 : 3 kΩ
Free
KVS TGT Mathematics Mini Mock Test
11.5 K Users
70 Questions 70 Marks 70 Mins

Detailed Solution

Download Solution PDF

Concept:

UJT Relaxation Oscillator:

F4 Vinanti Engineering 21.12.22 D7

The Unijunction Transistor or UJT for short is another solid-state three-terminal device that can be used in gate pulse, timing circuits, and trigger generator applications to switch and control either thyristors and triac’s for AC power control type applications.

Here;

RBB = RB1 + RB2

η = RB1/(RB1 + RB2)

Calculation:

RBB = 5 kΩ 

η = 0.6 

Vv = 1 V 

Iv = 10 mA

Ip = 10 μA 

Then;

η = RB1/(RB1 + RB2) = η = RB1/RBB

∴ RB1 = ηRBB = 0.6 × 5 = 3 kΩ 

 

Latest KVS TGT Updates

Last updated on May 8, 2025

-> The KVS TGT Notiifcation 2025 will be released for 16661 vacancies.

-> The application dates will be announced along with the official notification.

-> Graduates with B.Ed or an equivalent qualification are eligible for this post.

-> Prepare with the KVS TGT Previous Year Papers here.

Get Free Access Now
Hot Links: teen patti chart teen patti cash teen patti master 51 bonus