Question
Download Solution PDFIn the following governor, three straight leaf springs are arranged at equal angular intervals round the spindle and each spring carries a weight at the centre. The weights move outwards and the springs bend as they rotate about the spindle axis with increasing speed.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Pickering governor
The Pickering governor is shown in Fig. It consists of three straight leaf springs arranged at equal angular intervals around the spindle. Each spring carries a weight at the centre. The weights move outwards and the springs bend as they rotate about the spindle axis with increasing speed.
It is mostly used for driving gramophones.
Let m= mass attached at the centre of the leaf spring
a = distance from the spindle axis to the centre of gravity of the mass when the governor is at rest
δ = deflection of the centre of the leaf spring
ω = angular speed of the spindle
h = lift of the sleeve
The deflection of a leaf spring with both ends fixed and carrying a central load W, is given by
\(\delta = \frac{WL^3}{192 El}\)
Last updated on May 19, 2025
-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been released on its official website.
-> JKSSB JE exam will be conducted on 10th August (Civil), and on 27th July 2025 (Electrical).
-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering.
-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025.
-> JKSSB JE Online Application form will be activated from18th May 2025 to 16th June 2025
-> Candidates who are preparing for JKSSB JE can download syllabus PDF from official website of JKSSB.
-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.
-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.