Question
Download Solution PDFIn three-phase power measurement in a delta-connected load using 2 watt meters, when the power factor of the load is zero, readings of 2 watt meters will be __________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFTwo Wattmeter Method of Power Measurement
The wattmeter meter readings are:
\(W_1=V_LI_Lcos(30-Ï•)\)
\(W_2=V_LI_Lcos(30+Ï•)\)
where, \(ϕ=tan^{-1}({√{3}(W_1-W_2)\over W_1+W_2})\)
The power factor is given by cosϕ.
Calculation:
Given, cosÏ• = 0 ⇒ Ï• = 90°
\(W_1=V_LI_Lcos(30-Ï•)\)
\(W_1=V_LI_Lcos(30-90)\)
\(W_1={1\over 2}\times V_L\times I_L\)
\(W_2=V_LI_Lcos(30+Ï•)\)
\(W_2=V_LI_Lcos(30+90)\)
\(W_2=-{1\over 2}\times V_L\times I_L\)
If we multiply both W1 and W2 by √3, then:
\(W_1={\sqrt{3}\over 2}\times V_L\times I_L\) and \(W_2=-{\sqrt{3}\over 2}\times V_L\times I_L\)
Last updated on May 29, 2025
-> MPPGCL Junior Engineer result PDF has been released at the offiical website.
-> The MPPGCL Junior Engineer Exam Date has been announced.
-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.
-> Candidates can apply online from 23rd December 2024 to 24th January 2025.
-> The selection process includes a Computer Based Test and Document Verification.
-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.