'n' निरीक्षणाचा अर्थ \(\bar x\) आहे. जर 'n + 1' आणि '2n - 3' ची दोन निरीक्षणे जोडली, तर सरासरी समान राहते, तर 'n' चे मूल्य किती?

  1. \(\frac{{2 + 2\bar x}}{3}\)
  2. \(\frac{{2 - 2\bar x}}{3}\)
  3. \(\frac{{2 + 3\bar x}}{3}\)
  4. \(\frac{{3 - 2\bar x}}{3}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{{2 + 2\bar x}}{3}\)
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दिलेल्याप्रमाणे:

'n' निरीक्षणाचा अर्थ आहे

संकल्पना:

मध्यकाची संकल्पना

वापरलेले सूत्र:

सरासरी = बेरीज/एकूण

गणना:

'n' निरीक्षणांची बेरीज = \(n\bar x\)

जेव्हा 'n + 1' आणि '2n - 3' जोडले जाते तेव्हा निरीक्षणांची बेरीज = \(n\bar x + \left( {n + 1} \right) + \left( {2n - 3} \right) = \left( {n + 2} \right)\bar x\)

\(\begin{array}{l} n\bar x + 3n - 2 = n\bar x + 2\bar x\\ \Rightarrow 3n - 2 = 2\bar x \end{array}\)

\(\Rightarrow n = \frac{{2 + 2\bar x}}{3}\)
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