Question
Download Solution PDFPerson A tells the truth 30% of the times and B tells the truth 40% of the times, independently. What is the minimum probability that they would contradict each other?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Let A: A tells the truth, Ac = A lies
B: B tells the truth, Bc = B lies
So P(A) = 30% =
and P(Ac) = 1 -
Similarly,
P(B) = 40% =
and P(Bc) = 1 -
Therefore that the minimum probability that they would contradict each other i.e., one tell the truth and other lies
= P(A) × P(Bc) + P(B) × P(Ac)
=
Option (3) is correct
Last updated on Jun 23, 2025
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