Question
Download Solution PDFL1 మరియు L2 అనేవి సరళరేఖలు. వీటి సమీకరణాలు వరుసగా \(\rm \vec{r}=\vec{a}_1 +\lambda \vec{b}\) మరియు \(\rm r=\vec{a}_2 + \mu\vec{b}\) . అయిన ఈ రెండు రేఖల మధ్యనుండే అతి తక్కువ దూరం?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFపద్ధతి:
- రెండు రేఖలు సమాంతరంగా ఉంటే, వాటి మధ్య దూరం స్థిరంగా ఉంటుంది.
- రెండు సమాంతర రేఖల మధ్య దూరం\(\rm \vec{r}=\vec{a}_1 +\lambda \vec{b}\) and \(\rm r=\vec{a}_2 + \mu\vec{b}\) : \(\rm d=\left|\dfrac{\vec{b}\times (\vec{a}_2-\vec{a}_1)}{|\vec{b}|}\right|\).
సాధన:
రెండు సమాంతర రేఖల మధ్య దూరం కోసం సూత్రాన్ని ఉపయోగించిన, \(\rm d=\left|\dfrac{\vec{b}\times (\vec{a}_2-\vec{a}_1)}{|\vec{b}|}\right|\).
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