The distance between the points (a cos θ, 0) and (0, a sin θ) will be:

Concept -

The distance between two points \((x_1, y_1)\) and \((x_2, y_2)\) in a 2D plane can be found using the distance formula:

\(\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)

Explanation -

In this case, the points are (a cos θ, 0) and (0, a sin θ)  So, applying the distance formula:
\(\begin{align*} \text{Distance} &= \sqrt{ (0 - a \cos \theta)^2 + (a \sin \theta - 0)^2 } \\ &= \sqrt{a^2 \cos^2 \theta + a^2 \sin^2 \theta} \\ &= \sqrt{a^2 (\cos^2 \theta + \sin^2 \theta)} \\ &= \sqrt{a^2} \\ &= |a| \end{align*}\)

Thus, the distance between the points (a cos θ, 0) and (0, a sin θ) is |a|.

Hence the option(1) is true.