The distance covered by a train in (5y - 1) hours is (125y3 - 1) km. The speed of the train is :

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SSC CGL 2022 Tier-I Official Paper (Held On : 02 Dec 2022 Shift 2)
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  1. (5y3 - 1) km/h
  2. (25y2 - 5y + 1) km/h
  3. (5y + 1) km/h
  4. (25y2 + 5y + 1) km/h

Answer (Detailed Solution Below)

Option 4 : (25y2 + 5y + 1) km/h
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PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
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Detailed Solution

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Given:

The distance covered by a train in (5y - 1) hours is (125y3 - 1) km. 

Concept used:

a3 - b3 = (a - b)(a2 + ab + b2)

Calculation:

Speed of the train

⇒ (125y3 - 1) ÷ (5y - 1)

⇒ 

⇒ 

⇒ (25y2 + 5y + 1) km/h

∴ The speed of the train is (25y2 + 5y + 1) km/h.

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