Question
Download Solution PDFएक ट्रेन द्वारा (5y - 1) घंटे में तय की गई दूरी (125y3 - 1) किमी है। ट्रेन की गति ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
एक ट्रेन द्वारा (5y - 1) घंटे में तय की गई दूरी (125y3 - 1) किमी है।
प्रयुक्त अवधारणा:
a3 - b3 = (a - b)(a2 + ab + b2)
गणना:
ट्रेन की गति
⇒ (125y3 - 1) ÷ (5y - 1)
⇒ \(\frac {(5y)^3 - 1}{(5y - 1)}\)
⇒ \(\frac {(5y - 1)(25y^2 + 5y + 1)}{(5y - 1)}\)
⇒ (25y2 + 5y + 1) किमी/घंटा
∴ ट्रेन की गति (25y2 + 5y + 1) किमी/घंटा है।
Last updated on Jun 13, 2025
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