The midpoint of a rigid link of a mechanism moves as a translation along a straight line, from rest, with a constant acceleration of 5 m/s². The distance covered by the said midpoint in 5 s of motion is

Concept:

Distance covered by translation, \({\rm{S\;}} = {\rm{\;u}} \times {\rm{t\;}} + {\rm{\;}}\frac{1}{2}a{t^2}\)

u is the initial motion, t is the time and a is the acceleration

Calculation:

Given u = 0, a = 5 m/s² and t = 5 s

\({\rm{S\;}} = {\rm{\;u}} \times {\rm{t\;}} + {\rm{\;}}\frac{1}{2}a{t^2} = \frac{1}{2} \times 5 \times {5^2} = 62.5\;m\)