Question
Download Solution PDFThe relation among minimum detectable signal (MDS), IF bandwidth (BW) and noise figure (NF) of a spectrum analyzer is
This question was previously asked in
UPSC ESE (Prelims) Electronics and Telecommunication Engineering 19 Feb 2023 Official Paper
Answer (Detailed Solution Below)
Option 3 : MDS = -114 dBm + 10 log (BW/1 MHz) + NF
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Detailed Solution
Download Solution PDF- Minimum detectable signal (MDS) refers to the smallest signal power that a receiver or measurement system can reliably detect in the presence of noise.
- In the context of a spectrum analyze, MDS represents the weakest signal that can be distinguished from the background noise.
MDS = 10\(\times\)log10 (\(KT\over 1mW\))+ Noise figure + 10\(\times\)log10 (Bandwidth)
MDS = minimum detectable signal in dBm.
K= Boltzmann's constant (-228\(\frac {dW} { V}\). Hz)
Noise figure in db.
T = Temperature in kelvin.
Bandwidth in Hz.
Here, option 3 is correct.
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