The voltage across a 500 Ω input circuit of an amplifier is 6 V and the output is 30 V across a 500 Ω load. What is the dB gain of the amplifier?

The correct answer is option 1):(13.98 dB)

Concept:

The gain of the amplifier will be

Gain = \(V_o \over V_{in}\)

Gain in dB = 20 log (gain)

where 

V₀ is the output voltage

V_in is the input voltage

Calculation:

Given 

V₀ = 30 V

V_in = 6 V

Gain = \(V_o \over V_{in}\)

= \(30 \over 6\)

= 5

Gain in dB = 20 log (gain)

= 20 log (5)

= 13.98 dB