Question
Download Solution PDFTwo bulbs of rating 230 V, 60 W and 230 V, 100 W are connected in parallel across supply mains. Identify the correct statement.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFPower dissipation in a lamp,
\(P = \frac{{{V^2}}}{R}\)
Since both bulbs are rated at the same voltage, we can say that resistance of each bulb is inversely proportional to its rated power. Therefore, the resistance of 60 W bulb (R60) is greater than the resistance of 100 W (R100) bulb.
Since lamps connected in parallel, the voltage across the both bulb is same.
The power dissipated across 60 W lamp, \({P_{60}} = \frac{{{V^2}}}{{{R_{60}}}}\)
The power dissipated across 100 W lamp, \({P_{100}} = \frac{{{V^2}}}{{{R_{100}}}}\)
As R60 > R100, the power dissipated across 100 W is greater than 60 W.
Hence 100 W bulb will glow brighter in parallel connection.Last updated on May 29, 2025
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