Two bulbs of rating 230 V, 60 W and 230 V, 100 W are connected in parallel across supply mains. Identify the correct statement.

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SSC JE EE Previous Year Paper 14 (Held On: 26 Sep 2019 Morning)
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  1. Neither bulb will glow
  2. The 60 W bulb will glow brighter
  3. The 100 W bulb will glow brighter
  4. Both will glow equally bright

Answer (Detailed Solution Below)

Option 3 : The 100 W bulb will glow brighter
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Power dissipation in a lamp,

\(P = \frac{{{V^2}}}{R}\)

Since both bulbs are rated at the same voltage, we can say that resistance of each bulb is inversely proportional to its rated power. Therefore, the resistance of 60 W bulb (R60) is greater than the resistance of 100 W (R100) bulb.

Since lamps connected in parallel, the voltage across the both bulb is same.

The power dissipated across 60 W lamp, \({P_{60}} = \frac{{{V^2}}}{{{R_{60}}}}\)

The power dissipated across 100 W lamp, \({P_{100}} = \frac{{{V^2}}}{{{R_{100}}}}\)

As R60 > R100, the power dissipated across 100 W is greater than 60 W.

Hence 100 W bulb will glow brighter in parallel connection.
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