Two channels, one with bit rate of 150 Mbps and another with bit rate of 300 Mbps, are to be multiplexed. The bit rate of link is : 

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  1. 150 Mbps
  2. 300 Mbps 
  3. 450 Mbps 
  4. 100 Mbps

Answer (Detailed Solution Below)

Option 3 : 450 Mbps 
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Detailed Solution

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Explanation:

Multiplexing of Channels

Definition: Multiplexing is a method used in telecommunications to combine multiple signals into one signal over a shared medium. The goal is to maximize the utilization of the medium and to efficiently manage the bandwidth. There are various types of multiplexing, including Time Division Multiplexing (TDM), Frequency Division Multiplexing (FDM), and others, depending on how the signals are combined and transmitted.

Working Principle: When two or more channels are multiplexed, their individual data streams are combined into a single data stream that can be transmitted over a single communication link. This process involves the allocation of the link’s bandwidth to the different channels, either by dividing the time (in TDM) or the frequency (in FDM) among them.

Example: In this specific case, we have two channels with bit rates of 150 Mbps and 300 Mbps respectively. When these two channels are multiplexed, their combined bit rate will be the sum of their individual bit rates.

Calculation:

To determine the bit rate of the link after multiplexing these two channels, we simply add their individual bit rates:

Bit rate of Channel 1 = 150 Mbps

Bit rate of Channel 2 = 300 Mbps

Bit rate of the link after multiplexing = Bit rate of Channel 1 + Bit rate of Channel 2

Bit rate of the link after multiplexing = 150 Mbps + 300 Mbps = 450 Mbps

Correct Option Analysis:

The correct option is:

Option 3: 450 Mbps

This option correctly represents the total bit rate of the link after multiplexing the two channels. The combined bit rate is the sum of the individual bit rates of the channels being multiplexed, which in this case is 150 Mbps + 300 Mbps = 450 Mbps

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