v = A sin (ωct + m sin ωmt) is the expression for

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ESE Electrical 2016 Paper 2: Official Paper
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  1. Amplitude modulated signal
  2. Frequency modulated signal
  3. Phase modulated signal
  4. Carrier signal used for modulation 

Answer (Detailed Solution Below)

Option 3 : Phase modulated signal
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Detailed Solution

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Analysis:

Let the carries signal Sc(t) = Ac sin ωct

The message signal m(t) = Am sin ωm t

So, the expression of FM is:

\({S_{fm}}\left( t \right) = {A_c}\sin \left( {{\omega _c}t + {k_f}\;\mathop \smallint \limits_0^t m\left( t \right)dt} \right]\) 

\({s_{fm}}\left( t \right) = {A_c}\sin \left( {{\omega _c}t + {k_f}{A_m}\mathop \smallint \limits_0^t \sin {\omega _m}t} \right]\) 

\({s_{fm}}\left( t \right) = {A_c}\sin \left[ {{\omega _c}t - \frac{{{k_f}{A_m}}}{{{\omega _m}}}\cos {\omega _m}t} \right]\) 

If m: modulation index then:

\(\therefore m = \frac{{{k_f}{A_m}}}{{{\omega _m}}}\) 

Sfm(t) = Ac sin [ωct – m cos ωm t]

So hence given expression is not FM signal.

Now,

The expression of PM is:

Spm(t) = Ac sin (ωct + kp m(t)]

= Ac sin (ωc t + kp Am sin ωm t)

If m is the modulation index, then:

Spm(t) = Ac sin (ωc t + m sin ωm t)      

∴ m = kp Am

Hence given expression is of PM signal.   

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