Compound Ratios MCQ Quiz - Objective Question with Answer for Compound Ratios - Download Free PDF

Last updated on Jun 5, 2025

Compound Ratios questions and answers can be tricky to solve. It requires patience and practice to solve Compound Ratio MCQs Quiz error-free. Testbook brings to you this set of Compound Ratio question answers so that our candidates never run out of practice material. With the given explanation of the solution to these Compound Ratio objective questions, you will learn how to save time while solving and also improve accuracy.

Latest Compound Ratios MCQ Objective Questions

Compound Ratios Question 1:

A, B, and C together have 60 toffees. A has 25 toffees, and C has 5 fewer toffees than B. How many toffees must be added to C so that the final number of toffees with A, B, and C is in the ratio 5 : 4 : 6, respectively?

  1. 29
  2. 22
  3. 15
  4. 11
  5. 19

Answer (Detailed Solution Below)

Option 3 : 15

Compound Ratios Question 1 Detailed Solution

Calculation

Total toffies B and C has = 60 – 25 = 35

Let total toffies B has = x

So, total toffies C has = x – 5

ATQ, [2x – 5] = 35

Or, 2x = 40, x = 20

Let y toffies added with C to found resultant ratio

So, [15 + y]/ 20 = [6/4]

Or, 15 + y = 30

So, y = 15

Compound Ratios Question 2:

If \(\frac{15}{18}=\frac{x}{6}=\frac{10}{y}=\frac{z}{30}\)then the value of x + y + z is equal to

  1. 25
  2. 37
  3. 42
  4. 40

Answer (Detailed Solution Below)

Option 3 : 42

Compound Ratios Question 2 Detailed Solution

Given:

\(\frac{15}{18}=\frac{x}{6}=\frac{10}{y}=\frac{z}{30}\)

Formula Used:

If \(\frac{a}{b} = \frac{c}{d}\), then ad = bc

Calculation:

\(\frac{15}{18} = \frac{x}{6}\)

⇒ \(15 \times 6 = 18 \times x\)

⇒ x = 5

\(\frac{15}{18} = \frac{10}{y}\)

⇒ \(15 \times y = 18 \times 10\)

⇒ y = 12

\(\frac{15}{18} = \frac{z}{30} \)

⇒ \(15 \times 30 = 18 \times z\)

⇒ z = 25

Value of x + y + z = 5 + 12 + 25 = 42

∴ The value of x + y + z is 42

Compound Ratios Question 3:

A certain amount of money is divided between A, B and C in the ratio 8 : 4 : 3. If A divides his share between D and E in the ratio of 9 : 7, what will be the ratio of C's share to D's?

  1. 4 : 5
  2. 3 : 4
  3. 2 : 3
  4. 6 : 7

Answer (Detailed Solution Below)

Option 3 : 2 : 3

Compound Ratios Question 3 Detailed Solution

Given:

The total amount is divided between A, B, and C in the ratio 8 : 4 : 3.

A divides his share between D and E in the ratio 9 : 7.

Formula used:

Profit = Time × Investment

Calculation:

Let the total amount of money be S.

A's share = (8 / (8 + 4 + 3)) × S = (8 / 15) × S

B's share = (4 / (8 + 4 + 3)) × S = (4 / 15) × S

C's share = (3 / (8 + 4 + 3)) × S = (3 / 15) × S

Now, A divides his share between D and E in the ratio 9 : 7.

So, D's share from A = (9 / (9 + 7)) × A's share = (9 / 16) × (8 / 15) × S

⇒ D's share = (72 / 240) × S = (3 / 10) × S

Now, we need to find the ratio of C's share to D's share:

C's share : D's share = (3 / 15) × S : (3 / 10) × S

⇒ Ratio = (3 / 15) × (10 / 3) = 2 / 3

∴ The ratio of C's share to D's share is 2 : 3.

Compound Ratios Question 4:

Rs. 2,730 is divided among A, B and C such that A receives half as much as B and C together receive and B receives two-fifth of what A and C together receive. The share of C (in Rs.) is more than that of A by:

  1. 110
  2. 90
  3. 130
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : 130

Compound Ratios Question 4 Detailed Solution

Given:

Total amount = Rs. 2730

A = (B + C)/2

B = 2/5 (A + C)

Formula used:

Ratio and Proportion

Calculations:

From the given information,

2A = B + C and 5B = 2A + 2C

Substituting 2A in the second equation,

5B = B + C + 2C

⇒ B = 3C/4

Now, substitute B back into 2A = B + C

2A = 3C/4 + C

⇒ A = 7C/8

Now, A + B + C = 2730

Substituting A and B in terms of C,

7C/8 + 3C/4 + C = 2730

⇒ 7C + 6C + 8C = 2730 * 8

⇒ 21C = 21840

⇒ C = 21840/21 = 1040

Similarly,

⇒ A = 7C/8 = 7 × 1040/8

A = 910

Difference = C - A = 1040 - 910 = 130

∴ C's share is Rs. 130 more than A's.

Compound Ratios Question 5:

Rs. 2,730 is divided among A, B and C such that A receives half as much as B and C together receive and B receives two-fifth of what A and C together receive. The share of C (in Rs.) is more than that of A by:

  1. 110
  2. 90
  3. 130
  4. 150

Answer (Detailed Solution Below)

Option 3 : 130

Compound Ratios Question 5 Detailed Solution

Given:

Total amount = Rs. 2730

A = (B + C)/2

B = 2/5 (A + C)

Formula used:

Ratio and Proportion

Calculations:

From the given information,

2A = B + C and 5B = 2A + 2C

Substituting 2A in the second equation,

5B = B + C + 2C

⇒ B = 3C/4

Now, substitute B back into 2A = B + C

2A = 3C/4 + C

⇒ A = 7C/8

Now, A + B + C = 2730

Substituting A and B in terms of C,

7C/8 + 3C/4 + C = 2730

⇒ 7C + 6C + 8C = 2730 * 8

⇒ 21C = 21840

⇒ C = 21840/21 = 1040

Similarly,

⇒ A = 7C/8 = 7 × 1040/8

A = 910

Difference = C - A = 1040 - 910 = 130

∴ C's share is Rs. 130 more than A's.

Top Compound Ratios MCQ Objective Questions

Rs.750 are divided among A, B and C in such a manner that A : B is 5 : 2 and B : C is 7 : 13. What is A’s share?

  1. Rs.140
  2. Rs. 350
  3. Rs. 250
  4. Rs. 260

Answer (Detailed Solution Below)

Option 2 : Rs. 350

Compound Ratios Question 6 Detailed Solution

Download Solution PDF

Given 

Total rupees = Rs 750 

Calculation

A : B = 5 : 2 

B : C = 7 : 13 

A : B : C = 5 × 7 : 2 × 7 : 2 × 13 = 35 : 14 : 26 

Total Sum = 750 

⇒ 35 x + 14x + 26x = 750 

⇒ x = 10 

So, A's share = 35 × 10 = Rs 350 

∴ The required answer is Rs 350 

If (a + 3b) : (2a + 4b) = 3 : 5, then (a - b) : (a + b) is equal to:

  1. 2 : 1
  2. 2 : 3
  3. 3 : 2
  4. 1 : 2

Answer (Detailed Solution Below)

Option 4 : 1 : 2

Compound Ratios Question 7 Detailed Solution

Download Solution PDF

Given:

(a + 3b) : (2a + 4b) = 3 : 5

Formula used:

if \(\frac{a}{b} = \;\frac{c}{d}\)

then, \(\;\;\frac{{a - b}}{{a + b}} = \;\frac{{c - d}}{{c + d}}\)

Calculation:

\(\frac{{\left( {a + 3b} \right)}}{{\left( {2a + 4b} \right)}} = \;\frac{3}{5}\)

⇒ 5 × (a + 3b) =  3 × (2a + 4b) 

⇒ 5a + 15b = 6a + 12b

⇒ a = 3b

⇒ \(\frac{a}{b} = \;\frac{3}{1}\)

⇒ \(\frac{{a - b}}{{a + b}} = \;\frac{{3 - 1}}{{3 + 1}}\)

⇒ \(\frac{{a - b}}{{a + b}} = \;\frac{2}{4} = \;\frac{1}{2}\)

⇒ (a - b) : (a + b) = 1 : 2

A person has some coins of Rs. 10, Rs. 5, and Rs. 2 denominations. The ratio of the products of the numbers of Rs. 10 and Rs. 5 coins, the numbers of Rs. 5 and Rs. 2 coins, and the numbers of Rs. 2 and Rs. 10 coins is 3 ∶ 4 ∶ 2 respectively. What could be the minimum amount of money this person has?

  1. Rs. 52
  2. Rs. 88
  3. Rs. 68
  4. Rs. 74

Answer (Detailed Solution Below)

Option 3 : Rs. 68

Compound Ratios Question 8 Detailed Solution

Download Solution PDF

Given:

The products of the numbers of Rs. 10 and Rs. 5 coins, the numbers of Rs. 5 and Rs. 2 coins, and the numbers of Rs. 2 and Rs. 10 coins is 3 ∶ 4 ∶ 2

Calculation:

Ratio = 3 : 4 : 2

By multiplying with 6 we get,

18 : 24 : 12

We write 18 : 24 : 12 as (6 × 3) : (6 × 4) : (4 × 3)

So, from this we can assume the number of 10 rupee coins are 3, number of 5 rupee coins are 6 and number of 2 rupee coins are 4

So, minimum possible amount could be 10 × 3 + 5 × 6 + 2 × 4

⇒ 30 + 30 + 8

⇒ 68

∴ The required answer is 68.

If a + b + c = 1904, a ∶ (b + c) = 3 ∶ 13 and b ∶ (a + c) = 5 ∶ 9, then what will be the value of c?

  1. 776
  2. 879
  3. 867
  4. 680

Answer (Detailed Solution Below)

Option 3 : 867

Compound Ratios Question 9 Detailed Solution

Download Solution PDF

Given : 

a + b + c = 1904

a ∶ (b + c) = 3 ∶ 13

b ∶ (a + c) = 5 ∶ 9

Calculation : 

⇒ a ∶ (b + c) = 3 ∶ 13   --------------(1)

⇒ b  ∶ (a + c) = 5 ∶ 9     ------------------(2)

By adding one on both LHS and RHS of both the equations,

⇒ a + b + c : b + c = 16 : 13

⇒ a + b + c : a + c = 14 : 9 

Now making (a : b : c) same we get

⇒ a + b + c : b + c = 16 : 13 = 16 × 7 : 13 × 7 = 112 :  91

⇒ a + b + c : a + c = 14 : 9 = 14 × 8 : 9 × 8 = 112 : 72

So, 112x = 1904

⇒ x = 1904/112 = 17

Now, b + c = 91 × 17 = 1547

⇒ a + c = 72 × 17 = 1224

Now a + b + c = 1904

⇒ a + 1547 = 1904, a = 357

⇒ b + 1224 = 1904, b = 680

Now 357 + 680 + c = 1904

⇒ c = 1904 - 357 - 680 = 867

∴ The correct answer is 867.

Alternate Method a + b + c = 1904

a ∶ (b + c) = 3 ∶ 13

a/(b + c)  + 1 = (3/13) +1

a+ b + c /(b + c) = 16/13  

1904/(b + c) = 16/13 

b+ c = 1547  (i)

similarly,
b ∶ (a + c) = 5 ∶ 9
a+ b + c /(a + c) = 14/9     

1904/(a + c) = 14/9 

a+ c = 1224  (ii)

adding Equation (i) & (ii)

a + b + c + c = 1547 +1224

1904 + c = 2771

c = 867

∴ The correct answer is 867.

If Rs. 686 is divided, into four parts, in proportions \(\frac{1}{2}\;:\frac{2}{3}\;:3\;:4,\) then find the first part is:

  1. Rs. 52
  2. Rs. 42
  3. Rs. 56
  4. Rs. 48

Answer (Detailed Solution Below)

Option 2 : Rs. 42

Compound Ratios Question 10 Detailed Solution

Download Solution PDF

⇒ (1/2) ∶ (2/3) ∶ 3 ∶ 4 = 3 ∶ 4 ∶ 18 ∶ 24

⇒ First part = {3/(3 + 4 + 18 + 24)} × 686 = (3/49) × 686 = Rs. 42

If a : (b + c) = 1 : 3 and c : (a + b) = 5 : 7, find the value of b : (c + a).

  1. 1 : 2
  2. 3 : 4
  3. 4 : 5
  4. 3 : 5

Answer (Detailed Solution Below)

Option 1 : 1 : 2

Compound Ratios Question 11 Detailed Solution

Download Solution PDF

a : (b + c) = 1 : 3      ---(1)

c : (a + b) = 5 : 7      ---(2)

Multiply by 3 in equation (1)

a : (b + c) = 3 : 9      ---(3)

From equation (2) and equation (3)

c = 5 and a = 3 

a + b = 7

3 + b = 7

b = 7 – 3 = 4

Now,

b : (c + a)

⇒ 4 : (5 + 3)

⇒ 4 : 8

⇒ 1 : 2

A sum of Rs. 3,780 is divided between A, B and C such that if their shares are decreased by Rs. 130, Rs. 150 and Rs. 200, respectively, then they are in the ratio of 5 : 2 : 4. What is the original share of C?

  1. Rs. 1,430
  2. Rs. 1,400
  3. Rs. 1,330
  4. Rs. 1,350

Answer (Detailed Solution Below)

Option 2 : Rs. 1,400

Compound Ratios Question 12 Detailed Solution

Download Solution PDF

Given

sum divided between A, B and C is 3780

Calculation

let the share of A, B and C is 5x , 2x and 4x after decrease

so, original share of A, B and C is (5x + 130), (2x + 150) and (4x + 200)

5x + 130 + 2x + 150 + 4x + 200 = 3780

⇒ 11x + 480 = 3780

⇒ 11x = 3780 - 480

⇒ 11x = 3300

⇒ x = 300

Original share of C = (4x + 200)

⇒ (4 × 300 + 200)

⇒ 1200 + 200

⇒ 1400

∴ The original share of C is 1400.

A bakery used to sell pastries at a price of Rs. 48 per piece. In the next month, the bakery reduced the price of the pastries. Due to this, the sale of the pastries increased in the ratio 5 ∶ 8. If the earning of the bakery from pastries increased in the ratio 4 ∶ 5, by how much is the price of the pastry reduced?

  1. Rs. 2.50
  2. Rs. 4.50
  3. Rs. 7.50
  4. Rs. 10.50

Answer (Detailed Solution Below)

Option 4 : Rs. 10.50

Compound Ratios Question 13 Detailed Solution

Download Solution PDF

Let the new price of the pastry be Rs. ‘x’

⇒ The ratio of old to the new price of pastry = 48 ∶ x

Now,

⇒ The ratio of earning of bakery = Ratio of sale of pastries × Ratio of the price of pastries

⇒ 4 ∶ 5 = 5 ∶ 8 × 48 ∶ x

∵ The compound ratio of ratios a ∶ b and c ∶ d is ac ∶ bd

⇒ 4/5 = 30/x

⇒ x = 30 × 5/4 = Rs. 37.50

∴ Price of the pastry is reduced by = 48 - 37.50 = Rs. 10.50

Sum of three numbers is 160 and these numbers are in the ratio of 1 : 3 : 4. Find the product of the numbers.

  1. 96000
  2. 90000
  3. 80000
  4. 88000

Answer (Detailed Solution Below)

Option 1 : 96000

Compound Ratios Question 14 Detailed Solution

Download Solution PDF

GIVEN:

Sum of three numbers is 160 and these numbers are in the ratio of 1 : 3 : 4.

CONCEPT:

Basic ratio concept.

CALCULATION:

Suppose the numbers are x, 3x and 4x respectively.

So,

x + 3x + 4x = 160

8x = 160

x = 20

Now,

Product = x × 3x × 4x = 20 × 60 × 80 = 96000

If (8/5) P = (7/4) Q = (4/3) R, then what is the ratio of the P, Q, and R?

  1. 48 : 25 : 23
  2. 35 : 32 : 42
  3. 29 : 27 : 33
  4. 45 : 26 : 22

Answer (Detailed Solution Below)

Option 2 : 35 : 32 : 42

Compound Ratios Question 15 Detailed Solution

Download Solution PDF

Given:

(8/5) P = (7/4) Q = (4/3) R

Calculation

Let, (8/5) P = (7/4) Q = (4/3) R = k

P = 5/8 k, Q = 4/7 k, R = 3/4 k

Then, P ∶ Q ∶ R = 5/8 k ∶  4/7 k ∶ 3/4 k

Now, let us take the LCM of (8, 7, 4) = 56

⇒ P ∶ Q ∶ R = (5 × 7) ∶ (4 × 8) ∶ (3 × 14)

Then P : Q : R = 35 : 32 : 42

∴  The required ratio of P: Q: R = 35 : 32 : 42.

Get Free Access Now
Hot Links: teen patti star login teen patti win teen patti comfun card online teen patti neta