A hard disk has a rotational speed 6000 rpm. Its average latency time is

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NIMCET 2016 Official Paper
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  1. 5 × 10-3 sec
  2. 0.05 sec
  3. 1 sec
  4. 0.5 sec

Answer (Detailed Solution Below)

Option 1 : 5 × 10-3 sec
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NIMCET 2020 Official Paper
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6000 rpm ≡ 6000 rotations per minute

6000 rotations → 1 minute

6000 rotations → 60 seconds

1 rotation → \({\rm{\;}}\frac{{60}}{{6000}}\; =10^{-2} s \) 

Average latency time = ½ rotation 

Average latency time = \(\frac{10^{-2}}{2} = \frac{10 \times 10^{-3}}{2} = 5 \times 10^{-3} s\)

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