Question
Download Solution PDFA hard disk has a rotational speed 6000 rpm. Its average latency time is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF6000 rpm ≡ 6000 rotations per minute
6000 rotations → 1 minute
6000 rotations → 60 seconds
1 rotation → \({\rm{\;}}\frac{{60}}{{6000}}\; =10^{-2} s \)
Average latency time = ½ rotation
Average latency time = \(\frac{10^{-2}}{2} = \frac{10 \times 10^{-3}}{2} = 5 \times 10^{-3} s\)
Last updated on Jun 2, 2025
-> NIMCET 2025 admit card will be declared on June 3, 2025. Candidates can download the hall ticket till June 8, 2025.
-> NIMCET 2025 exam is scheduled for June 8, 2025. It will be conducted in Computer-Based Test (CBT) mode and will consist of 120 multiple-choice questions.
-> NIMCET 2025 results will be declared on June 27, 2025.
-> Check NIMCET 2025 previous year papers to know the exam pattern and improve your preparation.