A teacher in his physics laboratory allotted an experiment to determine the resistance (G) of a galvanometer. Students took the observations for \(\frac{1}{3}\) deflection in the galvanometer. Which of the below is true for measuring the value of G?

  1. \(\frac{1}{3}\) deflection method cannot be used for determining the resistance of the galvanometer.
  2. \(\frac{1}{3}\) deflection method can be used and in this case the G equals to twice the value of shunt resistance(s).
  3. \(\frac{1}{3}\) deflection method can be used and in this case, the G equals to three times the value of shunt resistance(s).
  4. \(\frac{1}{3}\) deflection method can be used and in this case the G value equals to the shunt resistance(s).

Answer (Detailed Solution Below)

Option 2 : \(\frac{1}{3}\) deflection method can be used and in this case the G equals to twice the value of shunt resistance(s).
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JEE Main 04 April 2024 Shift 1
12.4 K Users
90 Questions 300 Marks 180 Mins

Detailed Solution

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CONCEPT:

The galvanometer is a sensitive device used to detect very low currents in the device. Its working is based on the principle in which a coil placed in a uniform magnetic field experiences a torque when an electric current is set up in it. The deflection of the coil is determined by a pointer attached to it, moving on the scale.

CALCULATION:

It is given that a teacher in his physics laboratory allotted an experiment to determine the resistance (G) of a galvanometer. The circuit is shown below;

F1 Savita UG Entrance 19-9-22 D2

We can see that G and S are parallel to each other, therefore, 

(I - Ig) S = IgG

IS - Ig S = Ig G

⇒ IS = Ig G + Ig S

⇒ IS = (G+S) Ig 

⇒ \(\frac{I}{I_g}= \frac{G+S}{S}\) 

⇒ \(\frac{I_g}{I}= \frac{S}{G+S}\) ------(1)

Now, a student took observations and gets a deflection of 1/3, therefore equation (1) becomes;

⇒ \(\frac{1}{3}= \frac{S}{G+S}\) 

⇒ G+S = 3S

⇒ G = 2S

Therefore, the 1/3 deflection method can be used and in this case, the G equals twice the value of shunt resistance(S).

Hence option 2) is the correct answer.

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