Question
Download Solution PDFDetermine the ohmmeter value in the given network when R = 1Ω.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
When R = 1 Ω, 4 Ω is in series with it.
4 Ω + 1 Ω = 5 Ω
Now, 5 Ω || 20 Ω
\(\frac{20 \times 5}{20+5} = 4 ~\Omega\)
At the end, 4 Ω in series with 2 & 12 Ω
So, 4 + 2 + 12 = 18 Ω
The ohmmeter value in the given network when R = 1Ω is 18 Ω
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