Find the reciprocal of the sum of the reciprocals of the given numbers.

\(\frac{2}{5}, \frac{5}{4}, \frac{6}{8}, \frac{6}{5}, \frac{9}{6}\)

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  1. \(\frac{82}{15}\)
  2. \(\frac{15}{92}\)
  3. \(\frac{15}{82}\)
  4. \(\frac{92}{15}\)

Answer (Detailed Solution Below)

Option 2 : \(\frac{15}{92}\)
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Detailed Solution

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Given:

\(\frac{2}{5}, \frac{5}{4}, \frac{6}{8}, \frac{6}{5}, \frac{9}{6}\)

Formula used:

Reciprocal of the sum of reciprocals of the given numbers:

Calculation:

Reciprocals: 5/2, 4/5, 8/6, 5/6, 6/9

Sum of reciprocals = 5/2 + 4/5 + 8/6 + 5/6 + 6/9

⇒ Sum = 5/2 + 4/5 + 4/3 + 5/6 + 2/3

⇒ Sum = 75/30 + 24/30 + 40/30 + 25/30 + 20/30

⇒ Sum = (75 + 24 + 40 + 25 + 20)/30

⇒ Sum = 184/30 = 92/15

So, reciprocal of sum = 1/(92/15) = 15/92

∴ The correct answer is option (2).

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