Question
Download Solution PDFFind the value of \(\rm (\sqrt{98}-\sqrt{72}+\sqrt{50})\div \sqrt{18}?\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
\(\dfrac{(\sqrt{98}-\sqrt{72}+\sqrt{50})}{\sqrt{18}}\)
Formula used:
Calculation:
\(\sqrt{98} = \sqrt{49 \times 2} = 7\sqrt{2}\)
\(\sqrt{72} = \sqrt{36 \times 2} = 6\sqrt{2}\)
\(\sqrt{50} = \sqrt{25 \times 2} = 5\sqrt{2}\)
\(\sqrt{18} = \sqrt{9 \times 2} = 3\sqrt{2}\)
⇒ \(\dfrac{(7\sqrt{2}-6\sqrt{2}+5\sqrt{2})}{3\sqrt{2}} = \dfrac{6\sqrt{2}}{3\sqrt{2}}\) = 2
∴ The correct answer is option (3).
Last updated on Mar 21, 2025
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