\(\frac{0.2\times 0.2\times 0.2+0.02 \times0.02\times 0.02}{0.4\times 0.4\times 0.4+0.04\times 0.04\times 0.04}+\frac{0.67\times 0.67\times 0.67-0.001}{0.67\times 0.67+0.067+0.01}=?\)

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NPCIL Assistant Grade-1 (Advance) Official Paper-II (Held On: 08 Sept, 2018)
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  1. 1.87
  2. 0.695
  3. 0.067
  4. 0.002

Answer (Detailed Solution Below)

Option 2 : 0.695
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NPCIL Assistant Grade 1 Computer Knowledge Subject Test - 01
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20 Questions 60 Marks 15 Mins

Detailed Solution

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Given:

\(\dfrac{(0.2 \times 0.2 \times 0.2 + 0.02 \times 0.02 \times 0.02)}{(0.4 \times 0.4 \times 0.4 + 0.04 \times 0.04 \times 0.04)} + \dfrac{(0.67 \times 0.67 \times 0.67 - 0.001)}{(0.67 \times 0.67 + 0.067 + 0.01)}\) = ?

Formula used:

Basic Arithmetic Operations

Calculations:

\(\dfrac{(0.2 \times 0.2 \times 0.2 + 0.02 \times 0.02 \times 0.02)}{(0.4 \times 0.4 \times 0.4 + 0.04 \times 0.04 \times 0.04)} + \dfrac{(0.67 \times 0.67 \times 0.67 - 0.001)}{(0.67 \times 0.67 + 0.067 + 0.01)}\) = ?

\(\dfrac{(0.008 + 0.000008)}{(0.064 + 0.000064)} + \dfrac{(0.300763 - 0.001)}{(0.4489 + 0.067 + 0.01)}\)

\(\dfrac{0.008008}{0.064064} + \dfrac{0.299763}{0.5259}\)

\(\dfrac{0.008008}{0.064064}\) + \(\dfrac{0.299763}{0.5259}\)

⇒ 0.125 + 0.570

⇒ 0.695

∴ The correct answer is option (2).

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