For a given specific energy E, the critical depth yc for a rectangular channel is given by

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BPSC AE Paper 6 (Civil) 14 Oct 2022 Official Paper
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  1. \(y_c\) = \(\frac{3}{2} E\)
  2. \(y_c\) = \(\frac{2}{3} E\)
  3. \(y_c\) = \(\frac{4}{5} E\)
  4. \(y_c\) = \(\frac{3}{4} E\)

Answer (Detailed Solution Below)

Option 2 : \(y_c\) = \(\frac{2}{3} E\)
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Detailed Solution

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Explanation

Specific energy is the total head with respect to the channel bottom. It is a summation of the velocity head and the depth of flow at a given cross-section. Specific energy has proven to be very useful in the analysis of open-channel flow.

For rectangular channel 

E= 1.5yc or (3/2)yc

or

yc = (2/3)E

Where E=  Specific energy , yC = Critical depth 

For triangular section 

E= 1.25yc

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