व्यंजक (0.3 - 0.2) (0.32 + 0.3 × 0.2 + 0.22) को सरल कीजिए।

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SSC Selection Post 2024 (Graduate Level) Official Paper (Held On: 20 Jun, 2024 Shift 3)
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  1. 0.035
  2. 0.027
  3. 0.019
  4. 0.053

Answer (Detailed Solution Below)

Option 3 : 0.019
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दिया गया है:

व्यंजक (0.3 - 0.2) (0.32 + 0.3 × 0.2 + 0.22) को सरल करना है।

प्रयुक्त सूत्र:

मूल अंकगणितीय संक्रियाओं और बीजीय सर्वसमिकाओं का उपयोग करने पर:

(a - b)(a2 + ab + b2) = a3 - b3

गणना:

दिया गया व्यंजक: (0.3 - 0.2) (0.32 + 0.3 × 0.2 + 0.22)

सबसे पहले, आंतरिक व्यंजक को सरल बनाते हैं:

0.32 + 0.3 × 0.2 + 0.22

0.09 + 0.06 + 0.04

0.19

अब, बाह्य व्यंजक को सरल करते हैं:

(0.3 - 0.2) × 0.19

0.1 × 0.19

⇒ 0.019

सही उत्तर विकल्प 3 है।

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