Question
Download Solution PDFइकाई शक्ति कारक पर 230 V एकल फेज ऊर्जा मीटर के लिए संतत भार धारा 20 A है। यदि मीटर डिस्क 2 घंटे में 2300 चक्कर लगाती है तो मीटर स्थिरांक ______ होगा।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना
1ϕ ऊर्जा मीटर का मीटर स्थिरांक निम्न द्वारा दिया जाता है:
\(Meter \space constant\space = {No. \space of \space revolutions \space in \space 1 \space hr\over No. \space of \space kW \space in \space 1 \space hr}\)
गणना
दिया गया है, V = 230 वोल्ट
I = 20 A
cos ϕ = 1
P = VI cos ϕ
P = 230 × 20 × 1 = 4.6 kW
1 घंटे में चक्करों की संख्या = 2300/2 = 1150
\(Meter \space constant\space = {1150 \over 4.6}\)
मीटर स्थिरांक = 250 चक्कर / kWh
Last updated on Jun 16, 2025
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