अवकल समीकरण \(\rm dy = \left ( 4 + y^{2} \right )dx\) का हल क्या है?

  1. \(\rm y = 2\tan \left ( x+C \right )\)
  2. \(\rm y = 2\tan \left ( 2x+C \right )\)
  3. \(\rm 2y = \tan \left ( 2x+C \right )\)
  4. \(\rm2 y = 2\tan \left ( x+C \right )\)

Answer (Detailed Solution Below)

Option 2 : \(\rm y = 2\tan \left ( 2x+C \right )\)
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Detailed Solution

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अवधारणा:

\(\rm \int \frac{1}{a^{2}+x^{2}}dx = \frac{1}{a}\tan ^{-1}\frac{x}{a}+ C\) 

गणना:

दिया गया है : \(\rm dy = \left ( 4 + y^{2} \right )dx\) 

⇒ \(\rm \frac{dy}{4+y^{2}}= dx\) 

दोनों पक्षों का समाकलन करने पर, हमें मिलता है

\(\rm \int \frac{dy}{2^{2}+y^{2}}= \int dx\)

⇒ \(\rm \frac{1}{2}\tan^{-1}\frac{y}{2}= x+c\) 

⇒ \(\rm \tan^{-1}\frac{y}{2}= 2x+ 2c\)

⇒ \(\rm \tan^{-1}\frac{y}{2}= 2x+ C\) [∵ 2c = C]

⇒ \(\rm \frac{y}{2}= \tan(2x+ C)\)

 \(\rm y = 2\tan \left ( 2x+C \right )\) 

सही विकल्प 2 है।

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