If the direction ratios of two lines are (1, 2, 3) and (-2, 3, -4), Then the angle between the lines is: 

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  1. \(\rm \cos^{-1}\left(\frac{8}{\sqrt{406}}\right)\)
  2. \(\rm \cos^{-1}\left(-\frac{8}{\sqrt{406}}\right)\)
  3. \(\rm \cos^{-1}\left(-\frac{6}{\sqrt{406}}\right)\)
  4. \(\rm \cos^{-1}\left(\frac{6}{\sqrt{406}}\right)\)

Answer (Detailed Solution Below)

Option 1 : \(\rm \cos^{-1}\left(\frac{8}{\sqrt{406}}\right)\)
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Given:

The direction ratios of two lines are (1, 2, 3) and (-2, 3, -4)

Concept:

If given the direction ratios of two lines are \(\rm (a_1,b_1,c_1) \ and\ (a_2,b_2,c_2)\) then 

\(\rm \cos\theta=|\ ({\frac{a_1a_2+b_1b_2+c_1c_2}{\sqrt{a_1^2+b_1^2+c_1^2}\sqrt{a_2^2+b_2^2+c_2^2}}})|\)

Calculation:

The direction ratios of two lines are (1, 2, 3) and (-2, 3, -4) then

\(\rm a_1=1,b_1=2,c_1=3\ and\ a_2=-2,b_2=3,c_2=-4\)

Let the angle between the two lines be then

\(\rm \cos\theta=|\ ({\frac{a_1a_2+b_1b_2+c_1c_2}{\sqrt{a_1^2+b_1^2+c_1^2}\sqrt{a_2^2+b_2^2+c_2^2}}})|\)

\(\rm \implies \cos\theta=|{\frac{(1)(-2)+(2)(3)+(3)(-4)}{\sqrt{(1)^2+(2)^2+(3)^2}\sqrt{(-2)^2+(3)^2+(-4)^2}}}|\)

\(\rm \implies cos\theta= |{\frac{-8}{\sqrt{14}\sqrt{29}}}|\)

\(\rm \implies cos\theta= |{\frac{-8}{\sqrt{406}}}|\)

\(\rm \implies\theta=cos^{-1} ({\frac{8}{\sqrt{406}}})\)

Hence the option (1) is correct.

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