"m" men and "n" women are to be seated in a row so that no two women sit together. If m > n, then
number of ways in which they can be seated, is

This question was previously asked in
Rajasthan RAS Prelims 2023 Official Paper
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  1. \(\frac{\lfloor m \mid m-1}{\lfloor m-n+1}\)
  2. \(\frac{\lfloor m-1 \mid m+1}{\lfloor n\lfloor n-1} \)
  3. \(\frac{\lfloor m \mid m+1}{\lfloor m-n+1}\)
  4. \(\frac{\lfloor m \mid m-1}{\lfloor m-n-1}\)

Answer (Detailed Solution Below)

Option 3 : \(\frac{\lfloor m \mid m+1}{\lfloor m-n+1}\)
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Detailed Solution

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The Correct answer is Option 3. 

Key Points⇔ Arrange the men: There are m! ways to arrange the m men.
⇔ Gaps for women: After arranging the men, there are m + 1 gaps available for placing the women.
⇔ Choose gaps for women: We need to select n gaps out of m + 1 gaps. This can be done in (m+1) / n  ways.
Arrange the women: The n women can be arranged in n! ways in the selected gaps.

Total number of ways: = m! * ( m +1 / n ) * n !

Which simplifies to:

Final Answer:\(\frac{\lfloor m \mid m+1}{\lfloor m-n+1}\)

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