The active and lagging reactive components of current taken by an AC circuit from a 200 V supply are 40A and 30A, respectively. What is the value of admittance of the circuit?

Question

Question

This question was previously asked in

SSC JE Electrical 16 Nov 2022 Shift 3 Official Paper

Answer 1

The correct answer is option 4):(0.25 S)

Concept:

The active and reactive component I_A,I_R then current will e

I = \( \sqrt{I_A^2+I_R^2} \) A

The admittance Value is inverse of resistance

Y = \(I \over V\) ...S

Calculation:

Given

V = 200 V

IA = 40 A

IR = 30 A

I = \( \sqrt{I_A^2+I_R^2} \) A

= \( \sqrt{1600+ 900}\)

= 50

Y = \(I \over V\) S

= \(50 \over 200\)

= 0.25 S