The value of inductance needed to store 4kWh of energy in a coil carrying a 2000A current is:

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SSC JE Electrical 07 Jun 2024 Shift 3 Official Paper - 1
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  1. 7.2 H
  2. 7.2 × 106 H
  3. 72 H
  4. 720 H

Answer (Detailed Solution Below)

Option 1 : 7.2 H
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Detailed Solution

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Concept:

The energy stored in an inductor is given by:

\(E={1\over 2}LI^2\)

where, E = Energy

L = Inductance

I = Current

Calculation:

Given, E = 4 kWh = 

I = 2000 A

\(14400000={1\over 2}\times L\times 2000\times 2000\)

L = 7.2 H

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