The view factors F12 and F21, for the sphere of diameter d and a cubical box of length l = d as shown in the figure, respectively, are

F1 S.S Madhu 20.12.19 D6

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  1. \(1\;and\frac{\pi }{3}\)
  2. \(\frac{\pi }{3}and\;1\)
  3. \(1\;and\;\frac{\pi }{6}\)
  4. \(\frac{\pi }{6}and\;1\)

Answer (Detailed Solution Below)

Option 3 : \(1\;and\;\frac{\pi }{6}\)
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Detailed Solution

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Concept:

Shape Factor is defined as the fraction of radiation energy leaving a surface that reaches another surface, for example, F12 means the fraction of energy leaving surface 1 reaches surface 2.

Summation Rule:

F11 + F12 = 1

Reciprocity theorem:

A1 F12 = A2 F21 (A is the surface area)

Calculation:

Given:

side of the cube = a = l = d, diameter of sphere = d.

Since the sphere is completely enclosed by the cube, therefore,

F1 S.S Madhu 20.12.19 D6

Area of the cube of side a = 6a2

Area of sphere of diameter d = 4π(d/2)2

F12 = 1

By Reciprocal theorem:

A1 F12 = A2 F21

\(\begin{array}{l} 4\;π {\left( {\frac{d}{2}} \right)^2} \times 1 = 6 {d^2} \times{F_{21}}\\ {F_{21}} = \frac{π }{6} \end{array}\)

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