Thermodynamic process is shown below on a P-V diagram for one mole of an ideal gas. If V= 2V1 then ratio of temperature T2/T1 is: 

qImage28780

  1. \(\frac{1}{{\sqrt 2 }}\)
  2. \(\sqrt 2 \)
  3. \(1 \over 2\)
  4. 2

Answer (Detailed Solution Below)

Option 2 : \(\sqrt 2 \)
Free
JEE Main 04 April 2024 Shift 1
12.2 K Users
90 Questions 300 Marks 180 Mins

Detailed Solution

Download Solution PDF

Concept:  

We know that for a polytropic process equation is given as:

PVγ = K      -----(1)

Where P = pressure, V = volume, K = constant, γ = ratio of specific heats

PV = nRT ⇒ P = nRT/V      -----(2)

Calculations:

Given: 

 qImage28780

Here, V= 2V1 Then find T2/ T1 = ?

PV1/2 = K where γ = 1/2 

From equation(1) and (2) we get:  nRT/V1/2 = K      -----(3)

From equation (3) we get: T ∝ V1/2       -----(4)

⇒T2 / T1 = (V2 / V1)1/2     -----(4)

Put V= 2V1 in equation (4) we get:

T2 / T1 = (2V / V)1/2 = √2

Hence, option (2) is correct. 

Latest JEE Main Updates

Last updated on May 23, 2025

-> JEE Main 2025 results for Paper-2 (B.Arch./ B.Planning) were made public on May 23, 2025.

-> Keep a printout of JEE Main Application Form 2025 handy for future use to check the result and document verification for admission.

-> JEE Main is a national-level engineering entrance examination conducted for 10+2 students seeking courses B.Tech, B.E, and B. Arch/B. Planning courses. 

-> JEE Mains marks are used to get into IITs, NITs, CFTIs, and other engineering institutions.

-> All the candidates can check the JEE Main Previous Year Question Papers, to score well in the JEE Main Exam 2025. 

More Thermodynamic processes Questions

More Thermodynamics Questions

Get Free Access Now
Hot Links: teen patti gold downloadable content teen patti sequence master teen patti teen patti apk