Two inductively coupled coils have self-inductance L1 = 20H and L2 = 320H. Find the maximum possible mutual inductance between the coils.

This question was previously asked in
SSC JE Electrical 07 Jun 2024 Shift 3 Official Paper - 1
View all SSC JE EE Papers >
  1. 80 H
  2. 40 H
  3. 100 H
  4. 10 H

Answer (Detailed Solution Below)

Option 1 : 80 H
Free
RRB JE CBT I Full Test - 23
14.3 K Users
100 Questions 100 Marks 90 Mins

Detailed Solution

Download Solution PDF

Coefficient of coupling

The coefficient of coupling can be defined as a magnetic flux that is produced between two different coils while managing the flux successfully.

\(k={M\over \sqrt{L_1L_2}}\)

where, k = Coefficient of coupling

M = Mutual inductance

Land L2 = Self-inductance of two coils

The mutual inductance between the coils is maximum when k = 1

Calculation

Given, L1 = 20H and L2 = 320H

k = 1

\(k={M\over \sqrt{20\times 320}}\)

M = 80 H

Latest SSC JE EE Updates

Last updated on Jun 16, 2025

-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

Get Free Access Now
Hot Links: teen patti vip teen patti master 51 bonus teen patti club apk rummy teen patti teen patti club