Two coupled coils with L1 = L2 = 0.5 H have a coupling coefficient of K = 0.75. The turn ratio N1/N2 =?

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SSC JE EE Previous Year Paper 14 (Held On: 26 Sep 2019 Morning)
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  1. 4
  2. 0.5
  3. 2
  4. 1

Answer (Detailed Solution Below)

Option 4 : 1
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Detailed Solution

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Concept:

\(L = \frac{{{\mu _0}{N^2}A}}{l}\)

The self-inductance of a coil is given by

Where L is the self-inductance

N is the number of turns

A is the cross-sectional area

l is the length

Calculation:

The self-inductance is proportional to the square of the turns in a coil i.e. L ∝ N2

\(\Rightarrow \frac{{{L_1}}}{{{L_2}}} = \frac{{N_1^2}}{{N_2^2}}\)

Given that L1 = L2 = 0.5 H

⇒ N/ N2 = 1

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