Question
Download Solution PDFTwo hollow conducting spheres of radii R1 and R2 (R1 >> R2) have equal charges. The potential would be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
The potential of the given conduction sphere is written as;
V = \(\frac{1}{4 \pi \epsilon_o} \frac{Q}{R}\)
⇒ V = k \(\frac{ Q}{R}\)
Here V is the potential, Q is the charge, and k is the constant of proportionality.
CALCULATION:
According to the potential of the condition sphere we have;
V = k \(\frac{ Q}{R}\)
Where R is inversely proportional to the applied potential.
In this question, we have two hollow conducting spheres where R1 >> R2. The larger the radius the smaller the potential for the given conducting spheres.
So, R2 is having large potential than R1.
Hence, option 3) is the correct answer.
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