Two hollow conducting spheres of radii R1 and R2 (R1 >> R2) have equal charges. The potential would be:

  1. dependent on the material property of the sphere
  2. more on bigger sphere
  3. more on smaller sphere
  4. equal on both the spheres

Answer (Detailed Solution Below)

Option 3 : more on smaller sphere
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Detailed Solution

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CONCEPT:

The potential of the given conduction sphere is written as;

V = \(\frac{1}{4 \pi \epsilon_o} \frac{Q}{R}\)

⇒ V = k \(\frac{ Q}{R}\)

Here V is the potential, Q is the charge, and k is the constant of proportionality.

CALCULATION:

According to the potential of the condition sphere we have;

 V = k \(\frac{ Q}{R}\)

Where R is inversely proportional to the applied potential.

In this question, we have two hollow conducting spheres where R1 >> R2. The larger the radius the smaller the potential for the given conducting spheres.

So, R2 is having large potential than R1.

Hence, option 3) is the correct answer.

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