Which of the following is true with regard to self-locking screw?

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  1. The friction angle is equal to or greater than the Lead angle.
  2. The friction angle is less than the Lead angle.
  3. The friction angle is half of the Lead angle.
  4. The friction angle is 1 / 3rd of the Lead angle.

Answer (Detailed Solution Below)

Option 1 : The friction angle is equal to or greater than the Lead angle.

Detailed Solution

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Explanation:

Self-locking screw:

The power screw in which an effort is required to lower a load is known as a self-locking screw.

Eg. Screw jack

F1 Ashik Madhu 21.08.20 D1

P = Force require to lower a body, W = Weight of the body to be lowered, N = Normal force

μN = Friction force between body and screw, dm = Mean diameter of a screw, α = Lead angle

l = Lead i.e. distance travelled by screw along the axis in one rotation, πdm = Distance travelled by a point in screw in one rotation.

 The effort required to lower a body is given by ⇒ P = W × tan (ϕ - α )

where ϕ = friction angle and μ = tan ϕ is co-efficient of friction.

F1 Ashik Madhu 21.08.20 D2

The tangent of the helix angle is given by ⇒ \(\tan \alpha = \frac{l}{{\pi {d_m}}}\)

The Torque required to lower the body is given by –

Mt = Force × perpendicular distance

\({M_t} = P \times \frac{{{d_m}}}{2}\)

\({M_t} = \frac{{W{d_m}}}{2}\tan \left( {\phi - \alpha } \right)\)

When ϕ ≥ α, the torque required is positive and the condition is known as “Self-locking”.

tan ϕ ≥ tan α

\( ⇒ \mu \ge \;\frac{l}{{\pi {d_m}}}\)

 A screw will be self-locking if the coefficient of friction is equal to or greater than the lead angle.

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