Number Series MCQ Quiz - Objective Question with Answer for Number Series - Download Free PDF

The Pattern of the series is:

1 × 1 = 1,

1 × 2 = 2,

2 × 3 = 6,

6 × 4 = 24,

24 × 5 = 120,

120 × 6 = 720,

Solution:

Given Series: 9600, 26400, 76600, 199650, 549037.5

Logic Used: 

9600 × [11 / 4] = 26400 

26400 × [11 / 4] = 72600 

72600 × [11 / 8] = 199650 so on….

So, the wrong number is 76600.

Solution:

Given Series: 456, 5016, 45144, 361138, 1580040

Logic Used:

456 × 11 = 5016

5016 × 9 = 45144

45144 × 7 = 316008

316008 × 5 = 1580040

So, the wrong number is 361138.

Calculation:

2978, ? , 746, 374, 188,95

Here logic used is:

2978           1490          746             374            188          95

          1588          744            372             186           93

                    ÷ 2            ÷ 2              ÷ 2              ÷ 2

∴ Missing tern is 1490.

Calculation:

154 - 147 = 7

147 - 136 = 11

136 - 123 = 13

123 - 106 = 17

The differences between consecutive terms are 7, 11, 13, and 17. These differences are increasing by prime numbers.

The next difference should be 5 (the previous prime number before 7).

Now, add 5 to 154 to find the missing number:

154 + 5 = 159

∴ The missing term in the series is 159.

Here, we have repeated series of the first 4 terms i.e. 1,2,3,4 and the sum becomes 10

⇒ Total number of such repeated series = 2004/4 = 501

⇒ Sum of the first 2004 terms = 501 × 10 = 5010

∴ Sum of the first 2007 terms = 5010 + 1 + 2 + 3 = 5016

In this question, We have to find the sum of 1, 2, 3, 4, 1, 2, 3, 4... at 2007-terms. At 2004-terms all four terms (1, 2, 3 and 4) repeat continuously but after 2004 only 1, 2, and 3 occurs for completing 2007 terms. therefore first we have to find the sum of 2004 terms and after we added sum of 1, 2 and 3 in the sum of 2004 terms.

Calculation:

The pattern of given series can be explained as:

2² + 1 = 5

3³ – 1 = 26

4² + 1 = 17

5³ -1 = 124

6² + 1 = 37

7³ - 1 = 342

∴ The value of ? is 17.

Hint

The given series follows the pattern shown below:

The logic used : Pattern used is Consecutive number is multiplied and divided alternatively by .5,1,1.5.. and so on

6 ÷ 0.5 = 12

12 × 1 = 12

12 ÷ 1.5 = 8

8 × 2 = 16

16 ÷ 2.5 = 6.4

6.4 × 3 = 19.2

2 + 2² = 6

6 + 2⁴ = 22

22 + 2⁸ = 278

278 + 2¹⁶ = 65814

∴ 278 will come in place of question mark.

Calculation:

⇒ 2³ + 2 = 10

⇒ 3³ + 3 = 30

⇒ 4³ + 4 = 68

⇒ 5³ + 5 = 130

⇒ 6³ + 6 = 222 

∴ The missing number is 222. 

The given series follows the pattern shown below:

3 + 2² = 7

7 – 4² = –9

–9 + 6² = 27

27 – 8² = –37

–37 + 10² = 63

Calculation:

The given seris following the pattern

⇒ 156 × 5 + 1 = 781

⇒ 157 × 5 - 2 = 783

⇒ 158 × 5 + 3 = 793

⇒ 159 × 5 - 4 = 791

⇒ 160 × 5 + 5 = 805

⇒ 161 × 5 - 6 = 799

∴ Wrong number in the given series is 800

First term of GP = √2

Common ratio = √10/√2 = √5

⇒ 7^th term = \(a{r^6} = \sqrt 2 \times {\left( {\sqrt 5 } \right)^6} = 125\sqrt 2 \)

∴ G7 = 125√2

Calculation:

The series follows the following pattern:

⇒ 79 + 29 = 108

⇒ 108 + 31 = 139

⇒ 139 + 37 = 176

⇒ 176 + 41 = 217

⇒ 217 + 43 = 260

∴ The value of ? is 260

Logic: Addition of Prime numbers

Additional Information

Calculation:

The series follows the following pattern

9 + 17 = 26

17 + 26 = 43

26 + 43 = 69

43 + 69 = 112

∴ The missing number is 43.