Problem on Age MCQ Quiz - Objective Question with Answer for Problem on Age - Download Free PDF

Given:

Lavanya got married 10 years ago.

Present age = 11/5 × age at marriage.

Son's age = 1/10 × Lavanya's present age.

Formula used:

Let Lavanya's age at marriage be x.

Present age = x + 10.

Present age = (6/5) × x.

Son's present age = (1/10) × Lavanya's present age.

Calculations:

Let Lavanya's age at marriage be x.

Lavanya's present age = x + 10.

Lavanya's present age = (6/5) × x.

⇒ x + 10 = (6/5) × x.

⇒ 10 = (6/5) × x - x.

⇒ 10 = (6x - 5x)/5.

⇒ 10 = x/5.

⇒ x = 10 × 5 = 50.

Lavanya's age at marriage = 50 years.

Lavanya's present age = 50 + 10 = 60 years.

Son's present age = (1/10) × 60.

⇒ Son's present age = 60/10.

⇒ Son's present age = 6 years.

∴ Her son's present age is 6 years.

Given:

Karan was born 3 years after his parent's marriage.

His father is 6 years older than his mother but 26 years older than Karan.

Karan is 12 years of age as on today.

Calculation:

According to question,

⇒ F = 6 + M

⇒ F = 26 + K 

Since now karan is 12 years old so,

⇒ K = 12,

⇒ F = 38,

⇒ M = 32

Now at the time of birth age will be ,

⇒ F = 26

⇒ M = 20 

Since karan was born 3 years after his parents marriage so

Age of motrher = 20 - 3 = 17

∴ 'The correct answer is 17 years.

Given:

The sum of the age of a father and the age of a son = 75 years

The product of their ages before 5 years = 750

Calculation:

Let the father's age be x 

Then, son's age be 75 - x.

Their age 5 years ago be x - 5 and 70 - x

Now, according to the question

⇒ (x - 5)(70 - x) = 750

⇒ 70x - x² - 350 + 5x = 750

⇒ x² - 75x + 1100 = 0

⇒ x² - 55x - 20x + 1100 = 0

⇒ x(x - 55) - 20(x - 55) = 0

⇒ (x - 55) (x - 20) = 0

⇒ x = 55 and 20

So, according to the options, the value of x = 55 years

∴ The present age of the father is 55 years.

Given:

Four years ago, Ram was two times as old as Shyam.

Six years later from now, Ram will be only 1.5 times as old as Shyam. 

Calculation:

Let the present age of ram is P and shyam is Q

Four years ago,

⇒ (P - 4 ) = 2 x (Q - 4)

⇒ (P - 4 ) = 2Q - 8

⇒ P - 2Q  = - 4  .....(1)

Six year later

⇒ (P + 6 ) = 1.5 x (Q + 6)

⇒ (P + 6 ) = 1.5Q +9

⇒ P -1.5Q = 3 ....(2)

Subtract equation 1 from 2

P -1.5Q - P + 2Q = 3 + 4

Q = 7 x 2 = 14

put the value of Q in equation 2

P -1.5 x 14 = 3

P = 24

The present age of Ram and Shyam respectively will be 24 and 14

Calculation

Let present ages of Pankaj and Niraj be x and y respectively.

After 4 years ratio will be 5:3

[x + 4] / [ y + 4 ] = 5/3

⇒ 3 (x + 4) = 5 (y + 4)

⇒3x + 12 = 5y + 20

⇒3x − 5y = 8      ...  (1)

2 years ago, ratio was 9:17

(x − 2)/ (y − 2) = 9 / 17

⇒17(x − 2) = 9(y − 2)

⇒17x – 34 = 9y − 18

⇒17x − 9y = 16     ... (2)

x = 33

y = 21

present ages of Pankaj and Niraj be 33 and 21 respectively.

Let the ages of the man and his wife be 5x and 8x respectively.

After ten years,

ratio of the man and his wife will be 2 : 3;

⇒ (5x + 10) / (8x + 10) = 2 : 3

Hence, x = 10

The ages of the man and his wife are 50 and 80 respectively.

Given:

Four years ago age ratio of Ram and Rahul = 3 : 4

Present age ratio of Ram and Rahul = 17 : 22

Calculation:

Four years ago age ratio of Ram and Rahul = 3x : 4x

According to the question

(3x + 4)/(4x + 4) = 17/22

⇒ 22 × (3x + 4) = 17 × (4x + 4)

⇒ 66x + 88 = 68x + 68

⇒ 68x – 66x = 88 – 68

⇒ 2x = 20

⇒ x = 10

Present age of Ram = 3 × 10 = 30 + 4 = 34

Present age of Sunil = 34 – 5 = 29 years 

∴ the correct answer is 29 years.

Shortcut Trick 

Many students ignore to read full question, So please read full question before solving it. 
In the last line of question there is mentioned that Ram is 5 years older than Sunil. 
So if you Calculate Ram's age than you also can calculate Sunil's age.

Given:

Karan was born 3 years after his parent's marriage.

His father is 6 years older than his mother but 26 years older than Karan.

Karan is 12 years of age as on today.

Calculation:

According to question,

⇒ F = 6 + M

⇒ F = 26 + K 

Since now karan is 12 years old so,

⇒ K = 12,

⇒ F = 38,

⇒ M = 32

Now at the time of birth age will be ,

⇒ F = 26

⇒ M = 20 

Since karan was born 3 years after his parents marriage so

Age of motrher = 20 - 3 = 17

∴ 'The correct answer is 17 years.

Given:

Manish age = 20 years

Greece age = 20/5 = 4 years

Let after x years Manish will become three times as old as Greece:

(20 + x) = 3 × (4 + x)

20 + x = 12 + 3x

2x = 8

x = 4

After 4 years Manish's age will be 24 years and Greece's age 8 years.

When Manish's age is 24 years old he became three times as old as Greece.

Hence, the correct answer is "24".

Given:

Amita's father was 38 years old when she was born.

Her mother was 36 years old when her brother was born.

Her brother was four years younger than her.

Calculation:

Let the present age of Amita be P years.

So,

The age of her father = (38 + P) years

The age of her brother = (P - 4) years

The age of her mother = 36 + (P - 4) = (32 + P) years

Now, the age difference between her parents = (38 + P) - (32 + P) = 6 years

∴ The difference between the ages of her parents is 6 years.

Given:

(Man's age + 15 years) = 4(Man's age - 15 years)

Calculation:

Let the present age of the man be x years

According to the question,

⇒ (x + 15) = 4(x - 15)

⇒ x + 15 = 4x - 60

⇒ 4x - x = 15 + 60

⇒ 3x = 75

⇒ x = 25

∴ The present age of man is 25 years.

Let the ages of Keshav and Danish after six years be 19x and 17x respectively

⇒ Present age of Keshav = (19x - 6) years

⇒ Present age of Danish = (17x - 6) years

According to question, age of Keshav 4 years ago is equal to present age of Danish

19x - 6 - 4 = 17x - 6

⇒ 2x = 4

⇒ x = 2

Present age of Keshav = (19 × 2) - 6 = 32 years

Present age of Danish = (17 × 2) - 6 = 28 years

Sum of their ages = 32 + 28 = 60

∴ The sum of their ages is 60.

Given:

Wife was born 23 years ago (which means her present age is 23 years

Ratio of ages of Rahul and his wife 7 years from now will be 7 : 6

Calculation:

Let the present age of husband be x years.

Age of husband 7 years hence = x + 7

Present age of wife = 23 years

Age of wife after 7 years = 30 years

According to the question,

Ratio of ages of husband and wife 7 years from now = 7 : 6

⇒ (x + 7)/30 = 7/6

⇒ x + 7 = 35

⇒ x = 28 years

Given:

5 years ago, ratio of ages of A, B and C = 4 : 5 : 7.

Sum of their present ages = 135 years.

Concept used:

Total = Average × Number of entities

Calculation:

Let the common ratio be Q.

So, 5 years ago, the ages of A, B, and C are 4Q, 5Q, and 7Q respectively.

Now, their present ages are (4Q + 5), (5Q + 5), and (7Q + 5) respectively.

According to the question,

(4Q + 5) + (5Q + 5) + (7Q + 5) = 135

⇒ 16Q + 15 = 135

⇒ 16Q = 135 - 15

⇒ 16Q = 120

⇒ Q = 7.5

The present age of B = (5 × 7.5 + 5) = 42.5 years

The present age of C = (7 × 7.5 + 5) = 57.5 years

Now, 3 years from now, the sum of the ages of B and C

⇒ (42.5 + 3) + (57.5 + 3)

⇒ 106 years

∴ After 3 years from now, the sum of the ages of B and C will be 106 years.

Given:

Jitin's age 3 years from now will be double the average of Jitin's current age and his age 8 years ago.

Formula:

Average of two numbers = (sum of two numbers)/2

Solution:

Let Jitin's current age be a.

Then, Jitin's age 3 years from now will be a + 3.

The average of Jitin's current age and his age 8 years ago is:

(a + (a - 8))/2 = (2a - 8)/2 = a - 4

Jitin's age 3 years from now will be double the average of Jitin's current age and his age 8 years ago. So, we have:

a + 3 = 2(a - 4)

a + 3 = 2a - 8

11 = a

Therefore, Jitin's current age is 11.

Jitin's age 5 years ago is 11 - 5 = 6.

∴ The answer is 6.