Question
Download Solution PDFA steel bar with the area of cross - section 500 mm2 is acted upon by the forces shown in the figure below. What is the total elongation in the bar if the value of Young's modulus is 200 GPa?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Elongation in a Prismatic Bar is given by,
\(δ l = \frac{Pl}{AE}\)
where δl = change in length of the bar, P = Applied Load, l = initial length of the bar, A = Cross-section area of bar, E = Modulus of Elasticity
For bars in series, δltotal = ∑δl
Calculation:
Given:
Cross-section area (A) = 500 mm2, E = 200 GPa
δl = δl1 + δl2 + δl3
⇒ δl = \( \frac{P_1l_1}{AE}\) + \( \frac{P_2l_2}{AE}\) + \( \frac{P_3l_3}{AE}\)
⇒ δl = \(\frac{1}{500~\times~200~\times~10^3}\) \(\times~[(50~\times~10^3~\times~600)~+~(35~\times~10^3~\times~1000)~+~(45~\times~10^3~\times~1250)]\)
⇒ δl = 1.2125 mm
Last updated on May 28, 2025
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