Eight capacitors of the same value are connected in series. Their equivalent capacitance is 200 μF, the capacitance of each capacitor is _______.

Concept of Equivalent Capacitance in Series:

For capacitors connected in series, the equivalent capacitance (C_series) is given by:

1 / C_series = 1 / C₁ + 1 / C₂ + ... + 1 / C_n

For n identical capacitors each of capacitance C, the formula simplifies to:

C_series = C / n

Given Data:

• Number of capacitors (n) = 8
• Equivalent capacitance (C_series) = 200 μF

Calculation:

We know that:

C_series = C / n

Rearranging to solve for the capacitance of each capacitor (C):

C = C_series × n

Substituting the given values:

C = 200 μF × 8

C = 1600 μF

Conclusion:

Hence, the capacitance of each capacitor is 1600 μF = 16 × 10-4 F