Find the weight of a cylindrical iron container with base radius 12.6 cm and height is 4 m, where the weight of 1 cm³ of iron is 2 grams?

Given:

Radius of the base (r) = 12.6 cm

Height (h) = 4 m

Weight of 1 cm³ of iron = 2 grams

Formula:

Volume (V) = πr²h

Calculation:

Convert the height from meters to centimeters:

Height (h) = 4 m × 100 cm/m = 400 cm

Now, calculate the volume of the cylindrical iron container:

V = π × (12.6 cm)² × 400 cm = 2 × 63504 cm³ = 199584 cm³

Now, calculate the weight of the iron container:

Weight = Volume × Weight per cm³

Weight = 199584 cm³ × 2 grams/cm³ = 399168grams

Convert grams to kilograms (1 kg = 1000 grams)

Weight = 399168 grams / 1000 = 399.168 kg

So, the correct weight of the cylindrical iron container is approximately 399.168 kg.